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20-2x=4x^2
We move all terms to the left:
20-2x-(4x^2)=0
determiningTheFunctionDomain -4x^2-2x+20=0
a = -4; b = -2; c = +20;
Δ = b2-4ac
Δ = -22-4·(-4)·20
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*-4}=\frac{-16}{-8} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*-4}=\frac{20}{-8} =-2+1/2 $
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